The ';who'; command will generate a list of users
who are currently logged into the system, ie:
聽聽聽聽$ who
聽聽聽聽joe pts/4 Nov 27 10:35 (bearclaw)
聽聽聽聽fred pts/5 Nov 27 14:04 (:0.0)
聽聽聽聽fred pts/12 Nov 26 10:44 (:0.0)
聽聽聽聽tom pts/6 Nov 27 14:07 (chicken)
Since you only want the users (and presumably do
NOT want the other output fields), we can filter
this output (ie. using ';awk';).
Furthermore, to remove duplicate user names, we
can filter the output through ';uniq';:
聽聽聽聽$ cat /tmp/users
聽聽聽聽#!/bin/sh
聽聽聽聽
聽聽聽聽who | awk '{ print $1; }' | uniq
聽聽聽聽
聽聽聽聽$ chmod +x /tmp/users
聽聽聽聽
聽聽聽聽$ /tmp/users
聽聽聽聽joe
聽聽聽聽fred
聽聽聽聽tom
Tested on both Solaris and Linux.
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